j^2+2j=29

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Solution for j^2+2j=29 equation:


Simplifying
j2 + 2j = 29

Reorder the terms:
2j + j2 = 29

Solving
2j + j2 = 29

Solving for variable 'j'.

Reorder the terms:
-29 + 2j + j2 = 29 + -29

Combine like terms: 29 + -29 = 0
-29 + 2j + j2 = 0

Begin completing the square.

Move the constant term to the right:

Add '29' to each side of the equation.
-29 + 2j + 29 + j2 = 0 + 29

Reorder the terms:
-29 + 29 + 2j + j2 = 0 + 29

Combine like terms: -29 + 29 = 0
0 + 2j + j2 = 0 + 29
2j + j2 = 0 + 29

Combine like terms: 0 + 29 = 29
2j + j2 = 29

The j term is 2j.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2j + 1 + j2 = 29 + 1

Reorder the terms:
1 + 2j + j2 = 29 + 1

Combine like terms: 29 + 1 = 30
1 + 2j + j2 = 30

Factor a perfect square on the left side:
(j + 1)(j + 1) = 30

Calculate the square root of the right side: 5.477225575

Break this problem into two subproblems by setting 
(j + 1) equal to 5.477225575 and -5.477225575.

Subproblem 1

j + 1 = 5.477225575 Simplifying j + 1 = 5.477225575 Reorder the terms: 1 + j = 5.477225575 Solving 1 + j = 5.477225575 Solving for variable 'j'. Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + j = 5.477225575 + -1 Combine like terms: 1 + -1 = 0 0 + j = 5.477225575 + -1 j = 5.477225575 + -1 Combine like terms: 5.477225575 + -1 = 4.477225575 j = 4.477225575 Simplifying j = 4.477225575

Subproblem 2

j + 1 = -5.477225575 Simplifying j + 1 = -5.477225575 Reorder the terms: 1 + j = -5.477225575 Solving 1 + j = -5.477225575 Solving for variable 'j'. Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + j = -5.477225575 + -1 Combine like terms: 1 + -1 = 0 0 + j = -5.477225575 + -1 j = -5.477225575 + -1 Combine like terms: -5.477225575 + -1 = -6.477225575 j = -6.477225575 Simplifying j = -6.477225575

Solution

The solution to the problem is based on the solutions from the subproblems. j = {4.477225575, -6.477225575}

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